Re: [Haskell] Syntax Q: How do you share RHS's in case expressions!?

Ryan Newton wrote:

For example, in OCaml:

match 3 with 3 -> 99 | 4 -> 99

Can be abbreviated

match 3 with 3 | 4 -> 99

But I have had no luck figuring out how to do the same thing with:

case 3 of 3 -> 99; 4 -> 99

You can do this: let rhs = (some complicated expression) in case 3 of 3 -> rhs 4 -> rhs The complicated expression won't be evaluated unless one of the appropriate case alternatives is chosen. -- Ben