3 Mar
2005
3 Mar
'05
2:39 p.m.
Is the behavior of evaluating z unspecified? z = f (0, z) f x = case x of (1,1) -> z _ -> 0 Hugs and GHC agree that z evaluates to 0. However, if the first line is changed to z = f (z,0) then both implementations loop. In other words, the behavior depends on order of evaluation, which AFAIK is not specified.