Re: [Haskell] is $ a no-op?

"Jacques Carette" <carette@mcmaster.ca> writes:

...

-- |Apply list of functions to some value, returning list of results. -- It's kind of like an converse map. flist :: [a->b] -> a -> [b] flist fs a = map ($ a) fs

I have attempted, unsuccessfully, to write flist above in a point-free manner. Is it possible?

flist = flip (map . (flip ($)))