[Haskell] Why is newChan in the IO Monad?

Nothing actually happens when newChan is called except construction of a new datastructure. It would be nice to have non IO monad code be able to create a new Chan that gets passed to IO code that uses it somewhere else. Alternatively, is there a way to create a Chan outside the IO monad? -Alex- _________________________________________________________________ S. Alexander Jacobson mailto:me@alexjacobson.com tel:917-770-6565 http://alexjacobson.com