RE: [Haskell] is $ a no-op?

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-- It's kind of like an converse map.

I have attempted, unsuccessfully, to write flist above in a point-free manner. Is it possible?

Of course it is, but why? flist = flip (map . flip ($))

Some functions are simpler point-free, others are simpler with points. I was curious about this one (I like the pointwise version better). Also, the statement "It's kind of like a converse map" becomes quite clear from the point-free way to write it, while still not so obvious in the pointwise version. Jacques