Re: How overload operator in Haskell?

G'day all. On Thu, Jul 10, 2003 at 11:16:56PM -0700, Ashley Yakeley wrote:

As written, this is _not_ a good idea. Trust me, you end up having to put type annotations everywhere. Even (3 + 4 :: Integer) is ambiguous, you have to write (3 :: Integer) + (4 :: Integer).

But that's what default() is for! Cheers, Andrew Bromage