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                    2011
                
            
            
                10 Dec
                
                '11
                
            
            
            
        
    
                6:15 p.m.
            
        On Sat, Dec 10, 2011 at 12:33, Henning Thielemann wrote:
I have (x :: Set key) and (m :: Map key a) and want to remove all keys and corresponding values from m that are in x. I could solve it efficiently with a
differenceSet :: Map key a -> Set key -> Map key a
I have implemented this in the past, though it was certainly inefficient. It would be nice to have something similar and efficient. Regards, Sean